program 65: using linked lists

The need:
     This program is written just to show the use of linked lists. This program takes some numbers from the user stores them in nodes (creates linked list) and prints back for the user in the same order. So this program teaches us creating and accessing linked lists.

The code:  
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#include<stdio.h>
#include<stdlib.h>
struct node1
{
    int data;
    struct node1 *next;
};
typedef struct node1 node; //defining a datatype node
int main()
{
    int i,j;
    node *head,*temp1,*temp2; //declaring 3 pointers of type node
    head=NULL; //initialising head to null
    printf("Enter numbers to be stored. enter -999 to end.\n");
    while(i!=-999) //this while loop takes the numbers and creates list
    {    //loop runs untill user enters -999
        scanf("%d",&i);
        temp1=(node*)malloc(sizeof(node)); //allocation of a temporary node
        temp1->data=i; //filling data in node
        temp1->next=NULL; /*making pointer to next location NULL
        because there is no next location till now*/
        if(head==NULL) //the case when temp1 is very first node
        {
            head=temp1; //so head will be containing the address of first node permanently
            temp2=head; //temp2 is temporarily given address of first node
        }
        else /*the case when temp1 is not first node, we have a list of some members.
        Its kind of a line of persons in which a newcomer has to stand at the last
         so we have to go to last position starting from first*/
        {
            while(temp2->next!=NULL) //checking if temp2 is last node
            temp2=temp2->next; //loop exits if temp2 is last node
            temp2->next=temp1; //temp1 is appended to the list after last node
        }
    }
    printf("All the  numbers has been entered into linked list.\n");
    printf("press any key to view the list\n");
    fflush(stdin); //to flush previous undesired inputs from keyboard
    getchar(); //to give a pause to program untill user press any key
    printf("\nThe list is\n\n");
    temp2=head;
    while(temp2->next!=NULL) //this loop prints the list
    {
        printf("%d-->",temp2->data); //printing current member
        temp2=temp2->next; //jumping to next member in the list
    }
    printf("\n");
    return 0;
}

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The approach:  
The approach is very simple once you have read previous post. Everything has been written near statements as comments. Still this is a new topic so in case of any doubt please let me know.