program 64: use of pointer as array

The need:
     This is a simple program to show that pointer is equivalent to a one dimensional array of same datatype and how a pointer variable can be used as an array.

The code:  
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#include<stdio.h>
#include<stdlib.h>
#define max 5
main()
{
  int i;
  int *p,*q;
  p=(int *)malloc(max * sizeof(int));
  q=p;
  printf("Enter %d integers\n",max);
  for(i=0;i<max;i++)
  {
   printf("Enter number %d =>\t",i);
   scanf("%d",p++);
  }
  printf("\nyou entered\n");
  for(i=0,p=q;i<max;i++)
  {
   printf("%d whose address is %d\n",*p,p);
   p++;
  }
  return 0;
}

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The approach:  
This program takes 5 integers from user, store them in memory and prints back for user. This is a trivial task. Here I have shown how a pointer variable (in our case p) can be used  as an array of integers. This can be done for other data-types and even with derrived datatypes. First of all the pointer p is initialised and allocated sufficient memory (here using malloc function). After that five integers are scanned one by one and each time pointer p is incremented. In each increment p is automatically set to point to the next integer location in the memory. The initial value of p (starting location of array) is temporarily stored in other variable q. Which is later used to access the array to print it.